Saturday
July 26, 2014

Homework Help: Chemistry

Posted by Paris on Saturday, June 25, 2011 at 9:27pm.

A volume of 60.0 of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the KOH solution if 25.2 mL of 1.50M H2SO4 was needed? The equation is 2KOH+H2SO4-->K2SO4+2H2O. I cant seem to get the right answer so please, if you know how to do this explain it fully and work out the problem completely with numbers and equations.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chemistry - A volume of 80.0mL of aqueous potassium hydroxide (KOH) was titrated...
pcc - A volume of 40.0mL of aqueous potassium hydroxide (KOH) was titrated ...
Chemistry - A volume of 40.0 of aqueous potassium hydroxide (KOH) was titrated ...
Chemistry - A volume of 50.0 mL of aqueous potassium hydroxide was titrated ...
Chemistry - A volume of 70.0mL of aqueous potassium hydroxide(KOH) was titrated ...
Chemistry - A volume of 60.0mL of aqueous potassium hydroxide (KOH ) was ...
chemistry - A volume of 40.0 of aqueous potassium hydroxide was titrated against...
chemistry - What are the products formed when sulfuric acid solution reacts with...
intro to chem - The molarity of an aqueous solution of potassium hydroxide, KOH...
chemistry - 35.00mL of 0.250M KOH solution is required to completely neutralize ...

Search
Members