Sunday

February 1, 2015

February 1, 2015

Posted by **aimee** on Friday, June 24, 2011 at 5:45pm.

- physics -
**drwls**, Friday, June 24, 2011 at 7:46pmHorizontal distance covered = 8.95 m

= (Vo^2/g)*sin(2u)

Solve for the angle u.

Try deriving the formula. You will learn quite a bit in the process.

**Answer this Question**

**Related Questions**

physics - A long jumper travels 8.95 meters during a jump. He moves at 10.8 m/s ...

physics - school question? A long jumper travels 8.95 meters during a jump. He ...

physics - An Olympic long jumper leaves the ground at an angle of 23 degrees and...

physics - a long jumper takes off at an angle of 20 degrees with the horizontal ...

physics - At a track-and-field meet, the best long jump is measured as 8.00 m. ...

Physics - A jumper in the long-jump goes into the jump with a speed of 10m/s at ...

Physics - A jumper in the long-jump goes into the jump with a speed of 10m/s at ...

physics - An Olympic long jumper leaves the ground at an angle of 18.7 ° and ...

Physics - A long jumper leaves the ground at an angle of 24.3◦ to the ...

Physics - A long jumper leaves the ground at an angle of 20 degrees and travels ...