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a long jumper travels 8.95 meters during a jump. he moves at 10.8 m/s when starts his leap. at what angle from the horizontal must he have been moving when he started his jump? you may need the double angle formula: 2 sin u cos u- sin (2u)

  • physics -

    Horizontal distance covered = 8.95 m
    = (Vo^2/g)*sin(2u)
    Solve for the angle u.

    Try deriving the formula. You will learn quite a bit in the process.

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