a spring has a force constant of 20000 N/m how far must it be strectched for its potential energy to be 43 J??
PE=1/2 k x^2
x= sqrt (2*43/2E4) meters
To find the distance the spring must be stretched, we can use the equation for potential energy of a spring:
Potential energy (PE) = (1/2) * k * x^2
Where:
- PE is the potential energy (given as 43 J),
- k is the force constant of the spring (given as 20000 N/m),
- x is the distance the spring is stretched (what we're trying to find).
Rearranging the equation, we get:
x^2 = (2 * PE) / k
Now, substitute the given values into the equation:
x^2 = (2 * 43 J) / 20000 N/m
x^2 = 0.0043 m^2
To find x, take the square root of both sides:
x = sqrt(0.0043 m^2)
x ≈ 0.0656 m
Therefore, the spring must be stretched by approximately 0.0656 meters for its potential energy to be 43 J.