Posted by **cyn** on Friday, June 24, 2011 at 11:15am.

integrate 2/((2x-7)^2) from x=4 to 6

- calculus -
**drwls**, Friday, June 24, 2011 at 11:38am
Let 2x -7 = u

so dx = du/2

Integrand becomes

2/u^2*(du/2) = du/u^2 from u = 1 to 5.

= -1/u @ u = 5 -

(-1/u @ u = 1)

= 1 - 1/5 = 4/5

- calculus -
**Reiny**, Friday, June 24, 2011 at 11:39am
2/((2x-7)^2)

= 2(2x-7)^-2

integral of that is

-(2x-7)^-1 or -1/(2x-7)

and its value form x=4 to 6

= -1/5 + 1

= 4/5

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