Posted by cyn on Friday, June 24, 2011 at 11:15am.
integrate 2/((2x7)^2) from x=4 to 6

calculus  drwls, Friday, June 24, 2011 at 11:38am
Let 2x 7 = u
so dx = du/2
Integrand becomes
2/u^2*(du/2) = du/u^2 from u = 1 to 5.
= 1/u @ u = 5 
(1/u @ u = 1)
= 1  1/5 = 4/5 
calculus  Reiny, Friday, June 24, 2011 at 11:39am
2/((2x7)^2)
= 2(2x7)^2
integral of that is
(2x7)^1 or 1/(2x7)
and its value form x=4 to 6
= 1/5 + 1
= 4/5