Friday
April 18, 2014

Homework Help: Math

Posted by Kay on Thursday, June 23, 2011 at 8:25pm.

Can you help me with this? I did this many times and got different answers each time.

Find f.
f ''(x) = 3e^x + 3sin(x)
f(0) = 0
f(π) = 0

My work:
f ''(x) = 3e^x + 3sin(t)
f'(x) = 3e^x - 3cos(t) + C
f(x) = 3e^x -3sin(t) + Cx + D

0=f(0)= 3e^0 - 3sin(0) + C(0) + D
D=-3

0=f(π)= 3e^π - 3sin(π) + Cπ -3
C= (3-3e^π)/π

F(x) = 3e^x -3sin(x) + (3-3e^π)/π x - 3

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