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July 29, 2014

July 29, 2014

Posted by **Kay** on Thursday, June 23, 2011 at 8:08pm.

A particle is moving with the given data. Find the position of the particle.

a(t) = cos(t) + sin(t)

s(0) = 2

v(0) = 6

a(t) = cos(t) + sin(t)

v(t) = sin(t) - cos(t) + C

s(t) = -cos(t) - sin(t) + Cx + D

6 = v(0) = sin(0) -cos(0) + C

C=7

2= s(0) = -cos(0) - sin(0) + 7 (0) + D

D= 3

s(t) = -cos(t) - sin(t) + 7t + 3

- math -
**MathMate**, Friday, June 24, 2011 at 8:56amAll correct.

We can check backwards:

assume given:

s(t) = -cos(t) - sin(t) + 7t + 3

v(t)=s'(t)=sin(t)-cos(t)+7

a(t)=v'(t)=cos(t)+sin(t)

v(0)=sin(0)-cos(0)+7=0-1+7=6

s(0)=-cos(0)-sin(0) + 7(0) + 3 =-1+0+0+3=2

All correct!

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