Mike walks 100 meters north, then walks 30 meters south. After this, he walks another 10 meters north. What is the magnitude of his total displacement during this walk, in meters?

The answer is 80 because 100-30+10 is 80.

100N-30N+10N=80N

To find Mike's total displacement, we need to calculate the net distance and direction from his starting point to his final position.

First, let's represent north as positive and south as negative.

Mike walks 100 meters north, so his displacement is +100 meters.

Then, he walks 30 meters south, which means he moves in the opposite direction, resulting in a displacement of -30 meters.

Finally, he walks another 10 meters north, leading to a displacement of +10 meters.

To find the total displacement, we add up all the displacements:

+100 meters + (-30 meters) + 10 meters = 80 meters.

Therefore, the magnitude of his total displacement during this walk is 80 meters.

20