lim sin^-1 (3x^2-2x+1/6x^2-x+3)
x-> infinity
30 degrees or pi/6 radians
as x gets big, the numerator looks like 3x^2 and the denominator looks like 6 x^2
so we have sin^-1 (.5)
x-> infinity
as x gets big, the numerator looks like 3x^2 and the denominator looks like 6 x^2
so we have sin^-1 (.5)