If it requires 30.0 milliliters of 1.2 molar HCl to neutralize 20.0 milliliters of NaOH, what is the concentration of the NaOH solution?

Balanced equation: NaOH + HCl NaCl + H2O

0.60 M NaOH

0.80 M NaOH

1.3 M NaOH

1.8 M NaOH

MolarityNaOH*VolumeNaOH=MolarityHCl*volumeHCl

solve for molarityNaOH.

To find the concentration of the NaOH solution, we need to use the concept of stoichiometry and the provided information about the volume and concentration of HCl used for neutralization.

First, let's calculate the number of moles of HCl used in the neutralization reaction:
moles of HCl = volume of HCl (in liters) * concentration of HCl (in moles per liter)
moles of HCl = 30.0 milliliters * (1.2 moles per liter / 1000 milliliters per liter)
moles of HCl = 0.036 moles

According to the balanced equation, the stoichiometric ratio between HCl and NaOH is 1:1. This means that the moles of NaOH used in the reaction will also be 0.036 moles.

Next, let's calculate the concentration of NaOH:
concentration of NaOH = moles of NaOH / volume of NaOH (in liters)
concentration of NaOH = 0.036 moles / (20.0 milliliters / 1000 milliliters per liter)
concentration of NaOH = 1.8 moles per liter

Therefore, the concentration of the NaOH solution is 1.8 M NaOH.

The correct answer is 1.8 M NaOH.