Posted by Lilly on Tuesday, June 21, 2011 at 9:46pm.
Ba(OH)2 ==> Ba^2+ + 2OH^-
Ksp = (Ba^2+)(OH^-)^2
(Ba^2+) = 6.6E-3 from Ba(OH)2 and 1E-2 from BaCl2.
Solve for (OH^-)
So do you add the 6.6E-3 and 1E-2 together as the value for Ba^2+?
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