Posted by **TAINA** on Tuesday, June 21, 2011 at 3:23pm.

Joe has a collection of nickels and dimes that is worth $6.20. If the number of dimes was doubled and the number of nickels was decreased by 37, the value of the coins would be $8.85. How many nickels and dimes does he have?

- math -
**Reiny**, Tuesday, June 21, 2011 at 4:13pm
original number of nickels : x

original number of dimes : y

5x + 10y = 620 or

x + 2y = 124 (#1)

new case:

number of nickels : 2y

number of dimes : x-37

5(x-37) + 10(2y) = 885

5x + 20y = 1070

x + 4y = 214 (#2)

subtract: #2 - #1

2y = 90

y = 45

sub into #1

x + 2(45) = 124

x = 34

He had 34 nickels and 45 dimes

check: 34nickels + 45 dimes = 170+450 = 620

case 2:

90 dimes + (-3nickels) = 900 - 15 = 885

Even though there is a mathematical solution , and the answer can be verified arithmetically, the answer

makes no real sense

So I would say there is no solution, and the problem as stated is flawed.

- math -
**Henry**, Wednesday, June 22, 2011 at 2:36pm
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