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posted by RANDA Tuesday, June 21, 2011 at 12:07pm.
Given the quadratic function f(x) = x2 – 12x + 36, find a value of x such that f(x) = 25.
Given f(x) = x2 – 12x + 36 and f(x)=25, equate: 25 = x² - 12x + 36 x²-12x+11=0 (x-11)(x-1)=0 therefore x=11 or x=1
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