cslculate the molarity of a solution of 10.0g MgCl2 in a 300.0ml of solution
To calculate the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters).
First, convert the mass of MgCl2 to moles. The molar mass of MgCl2 is 95.211 g/mol.
10.0 g / 95.211 g/mol = 0.105 moles of MgCl2
Next, convert the volume of the solution from milliliters to liters.
300.0 ml = 300.0 ml / 1000 ml/L = 0.3 L
Now, use the mole-to-volume ratio to calculate the molarity.
Molarity (M) = moles of solute / volume of solution (in liters)
Molarity = 0.105 moles / 0.3 L = 0.35 M
Therefore, the molarity of the solution of 10.0 g MgCl2 in a 300.0 ml solution is 0.35 M.