As a baseball is being caught, its speed goes from 30 to 0 m/s in about 0.005 its mass is 0.145.
A) What is the baseballs acceleration in m/s^2 and in g's?
B) What is the size of force acting on it?
Yes it is .005 s. And you assume right it is 0.145 kg. I am sorry of not putting in the units. I am really struggling with Physics.
is a negative answer the answer is correct but the minus is missing.
To find the baseball's acceleration, we can use the equation for acceleration:
acceleration = (final velocity - initial velocity) / time
A) First, let's find the acceleration in m/s^2:
Given:
Initial velocity (u) = 30 m/s
Final velocity (v) = 0 m/s
Time (t) = 0.005 s
acceleration = (0 - 30) / 0.005
acceleration = -6000 m/s^2
Note that the negative sign indicates that the acceleration is in the opposite direction of the initial velocity.
B) To find the acceleration in g's, we need to convert it from m/s^2 to g's.
1 g = 9.8 m/s^2 (acceleration due to gravity)
acceleration in g's = acceleration / 9.8
acceleration in g's = -6000 / 9.8
acceleration in g's ≈ -612 g's
Again, the negative sign indicates the opposite direction of acceleration.
Now let's move on to finding the force acting on the baseball. We can use Newton's second law:
force = mass × acceleration
Given:
Mass (m) = 0.145 kg
Acceleration (a) = -6000 m/s^2 (or -612 g's in the same direction)
force = 0.145 × -6000
force ≈ -870 N
The negative sign indicates that the force is in the opposite direction of the motion.
So, the baseball's acceleration is approximately -6000 m/s^2 (or -612 g's) and the force acting on it is approximately -870 N.
Is the 0.005 number supposed to be seconds? What about the mass,
In physics, numbers without units are useless. You MUST learn that.
A) acceleration = a = (speed change)/(time) = 6000 m/s^2
Divide that by 9.8 m/s^2 for the number of g's
B) Use F = m*a
m = 0.145 kg, I assume
The force will be in newtons.