Posted by **CC** on Tuesday, June 21, 2011 at 12:15am.

John & Jane are married. The probability that John watches a certain television show is .4. The probability that Jane watches the show is .5. The probability that John watches the show, given that Jane does, is .7.

1) find probability that both John & Jane watch the show.

2) Find the probability that Jane watches the show, given that John does.

3) Do John & Jane watch the show independently of each other?

- Business Statistics -
**Nova**, Saturday, July 23, 2011 at 2:43am
A

P(Jane and John) = P(John | Jane) * P(Jane) = (0.7) * (0.5) = 0.35

B

P(Jane | John) = P(Jane and John) / P(John) = (0.35) / (0.4) = 0.875

C

P(Jane) * P(John) = (0.5) * (0.4) = 0.20

P(Jane and John) ≠ P(Jane) * P(John) = 0.35 ≠ 0.20

The two events are not independent do to the fact that P(Jane and John) ≠ P(Jane) X P(John). With that being said, John and Jane do not watch the show independently of each other.

## Answer this Question

## Related Questions

- statistics - The probability that a married man watches a certain television ...
- Physics - John is driving at a constant speed of 20.0 m/s when he passes Jane, ...
- Math/Physics - John is driving at a constant speed of 20.0 m/s when he passes ...
- Physics - Jane and John, with masses of 50 kg and 60 kg, respectively, stand on ...
- physics - Jane and John, with masses of 50kg and 68kg , respectively, stand on a...
- physics - Jane and John, with masses of 54kg and 63kg , respectively, stand on a...
- Math-Stat - Jane and Bob are on the same game show. They answer one question, ...
- 12 data management - 3 oeople - john joan and kim throw a ball to each other. ...
- statistics - For any married couple who are members of a squash club, the ...
- Algebra - A manufacture sells watches for $31. The manufacture has a fixed cost ...