Wednesday

December 17, 2014

December 17, 2014

Posted by **CC** on Tuesday, June 21, 2011 at 12:15am.

1) find probability that both John & Jane watch the show.

2) Find the probability that Jane watches the show, given that John does.

3) Do John & Jane watch the show independently of each other?

- Business Statistics -
**Nova**, Saturday, July 23, 2011 at 2:43amA

P(Jane and John) = P(John | Jane) * P(Jane) = (0.7) * (0.5) = 0.35

B

P(Jane | John) = P(Jane and John) / P(John) = (0.35) / (0.4) = 0.875

C

P(Jane) * P(John) = (0.5) * (0.4) = 0.20

P(Jane and John) ≠ P(Jane) * P(John) = 0.35 ≠ 0.20

The two events are not independent do to the fact that P(Jane and John) ≠ P(Jane) X P(John). With that being said, John and Jane do not watch the show independently of each other.

**Answer this Question**

**Related Questions**

statistics - The probability that a married man watches a certain television ...

Physics - John is driving at a constant speed of 20.0 m/s when he passes Jane, ...

Math/Physics - John is driving at a constant speed of 20.0 m/s when he passes ...

Physics - Jane and John, with masses of 50 kg and 60 kg, respectively, stand on ...

Math-Stat - Jane and Bob are on the same game show. They answer one question, ...

physics - Jane and John, with masses of 54kg and 63kg , respectively, stand on a...

statistics - For any married couple who are members of a squash club, the ...

12 data management - 3 oeople - john joan and kim throw a ball to each other. ...

Probability - A group of 90 students is to be split at random into 3 classes of ...

math of investment - Suppose the probability of a coin coming up heads is 2/5. ...