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chemistry

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calculate the weight of carbon momoxide having same number of O2 atoms as are present in 22g of carbon dioxide

  • chemistry - ,

    I assume O2 is an abbreviation for oxygen and you DON'T mean O2 atoms.
    22 g CO2 = 22/molar mass = 22/44 = 0.50 mole CO2. Since 1 mole CO2 contains 6.022E23 molecules of CO2, 0.50 mole will contain just half that number of CO2 molecules(3.011E23) and that number of atoms(6.022E23).
    So 1 mole CO should contain the same number of oxygen atoms.
    1 mole CO (28 grams) contains 6.02E23 molecules and 6.022E23 atoms oxygen.

  • chemistry - ,

    28g

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