Posted by **renee** on Monday, June 20, 2011 at 9:11pm.

difinite integral f(x)=(x^99+x^9+1)dx from x=0 to x=1

## Answer This Question

## Related Questions

- CALCULUS - difinite integral f(x)=dx/x from x=1 to x=e
- CALCULUS - difinite integral f(x)=2e^x from x=0 to x=ln 3
- CALCULUS - difinite integral f(x)=8-4ã-3:(X) from x=0 to x=8
- calculus - difinite integral f(x)=4-x from x=0 to x=4
- CALCULUS - difinite integral f(x)=1/y^2dy from x=1 to x=4
- CALCULUS - difinite integral f(x)=1/y^2dy from x=1 to x=4
- CALCULUS - difinite integral f(x)=8-4 cube root-3(x) from x=0 to x=8
- CALCULUS - difinite integral f(x)=8-4 cube root-3(x) from x=0 to x=8
- Calculus - If f(x) and g(x) are continuous on [a, b], which one of the following...
- Math/Calculus - How would I solve the following integral with the substitution ...

More Related Questions