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Physics

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5.A crate with a mass of 100kg accelerates with a magnitude of 2.0 m/s2 when it is pushed with a 250N.

a.What is magnitude of the force of friction opposing this motion?

b.What is the normal force of the crate?

c.Using a and b, find the coefficient of friction.

d.If the crate starts from rest, find the distance the crate travels in 3s.

  • Physics - ,

    a. Fn = ma = 100 * 2 = 200N = Net force.
    Fn=Fap - Ff=200, Fap = Force applied.
    250 - Ff = 200,
    -Ff = 200 - 250 = -50,
    Ff = 50N = Force of friction.

    b. Fc = mg = 100kg * 9.8N/kg = 980N =
    Force of the crate = Normal force.

    c. u = Ff/Fc 50/980 = 0.05 = coefficient of friction.

    d. d = Vo*t + 0.5at^2,
    d = 0 + 0.5*2*3^2 = 9m.

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