Posted by Anonymous on .
An object with 15 grams mass is immersed in benzene and suffers an apparent loss of mass 5g What is the approximate specific gravity of the object? (specific gravity of benzene = 0.7)
volume of object * .7 g/cm^3 = 5 g
V = 5/.7 = 7.14 cm^3
density = 15/7.14 = 2.1 g/cm^3
or specific gravity of 2.1 times water