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posted by Erin on Monday, June 20, 2011 at 5:40pm.
Determine the approximate maximum distance y=-0.01x2 +0.7x+6.1
-100 y = x^2 -70 x - 610 x^2 - 70 x = -100 y + 610 x^2 - 70 x + 1225 = -100y + 1835 (x-35)^2 = -100 y + 1835 vertex at x = 35 then y =18.35
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