Algebra
posted by Tommy .
Find the vertex of the function. Write your answer in the form (x,y). Use the slash mark as a fraction bar if necessary.
y=x^2x23

0=2x1
x=1/2, y=1/41/223=23.75
That is with Calculus. Now in Algebra, do this
y=x^2x + xxxx 23xxxxx
we are going to make a difference of prefect squares.
y=x^2x+1/4 231/4
y= (x1/2)^2  (sqrt22.75)^2
so clearly, this is a minumum at x=1/2