Thursday

October 30, 2014

October 30, 2014

Posted by **Martha** on Monday, June 20, 2011 at 2:29pm.

- Math -
**Henry**, Monday, June 20, 2011 at 9:07pmInvested $X @ 4%.

Invested $(26,000 - X) @ 2%.

0.04X + 0.02(26000 - X) = 680,

0.04X + 520 - 0.02X = 680,

0.02X = 680 - 520 = 160,

X = $8000 @ 4%.

26000 - 8000 = $18000 @ 2%.

**Answer this Question**

**Related Questions**

Math - The computer club invested $2200, part at 4.5% interest and the rest at 7...

math - A total of $9000 is invested: part at 6% and the remainder at 14%. How ...

Math - Joe invested $12,000, part at 6% interest and part at 8% interest. In the...

algebra - Larry Mitchel invested part of his $32,000 advance at 7% annual simple...

Math - Two investments are made totaling $4800. In the first year they yield a ...

iun - kim won 60,000 dollars. she invested part at 2 percent interest and the ...

Algebra - Joe invested $12000, part at 6% interest and part at 8% interest. In ...

Math - I hate word problems! Can anyone just change this Following word prob to...

Math - An investment advisor invested a total of $12,000, part at 2.5% annual ...

Math - O God I hate word problems! Is there any mechanical way to memorize word ...