Posted by **Martha** on Monday, June 20, 2011 at 2:29pm.

Part of 26000 invested at 4% interest and the rest at 2% interest yields 680.00

- Math -
**Henry**, Monday, June 20, 2011 at 9:07pm
Invested $X @ 4%.

Invested $(26,000 - X) @ 2%.

0.04X + 0.02(26000 - X) = 680,

0.04X + 520 - 0.02X = 680,

0.02X = 680 - 520 = 160,

X = $8000 @ 4%.

26000 - 8000 = $18000 @ 2%.

## Answer this Question

## Related Questions

- Math - The computer club invested $2200, part at 4.5% interest and the rest at 7...
- math - A total of $9000 is invested: part at 6% and the remainder at 14%. How ...
- Math - Joe invested $12,000, part at 6% interest and part at 8% interest. In the...
- algebra - Larry Mitchel invested part of his $32,000 advance at 7% annual simple...
- Math - Two investments are made totaling $4800. In the first year they yield a ...
- Algebra - Joe invested $12000, part at 6% interest and part at 8% interest. In ...
- iun - kim won 60,000 dollars. she invested part at 2 percent interest and the ...
- Math - I hate word problems! Can anyone just change this Following word prob to...
- Math - An investment advisor invested a total of $12,000, part at 2.5% annual ...
- Math - O God I hate word problems! Is there any mechanical way to memorize word ...

More Related Questions