The points A , B , C, D and E are located on a straight line in that order. The distance from A to E is 20cm. Te distance from A to D is 15cm. The distance from B to E is 10com. C is halfway between B and D. What is the distance from B to C?

First you draw a straight line (measured at 20 cm) with A at the beginning and E at the end. Then you know A to D is 15 cm so you can mark D. Next you measure from B to E. You know it is 10 cm so you can mark B. Since C is half-way between B and D, you can get the distance from B to C.

10 5 5
A----------B-----D-----E

Let's solve this step by step:

1. The distance from A to E is 20cm.
2. The distance from A to D is 15cm.
3. The distance from B to E is 10cm.
4. C is halfway between B and D.

To find the distance from B to C, we can use the fact that C is halfway between B and D. Since we know the distances between A and D and B and E, we can subtract them to find the distance from D to C.

Distance from D to C = (Distance from A to D) - (Distance from B to E)
= 15cm - 10cm
= 5cm

Therefore, the distance from B to C is 5cm.

To find the distance from B to C, we can use the information given in the problem:

1. Start with the given distances: AE = 20 cm and AD = 15 cm.

2. Since C is halfway between B and D, we can conclude that BC = CD.

3. To find BC, we need to find the value of CD.

4. Since AE = AD + DE, we can substitute the given values and get DE = AE - AD = 20 cm - 15 cm = 5 cm.

5. Since CD = DE, we can substitute the value of DE obtained in the previous step and get CD = 5 cm.

6. Now, since BC = CD = 5 cm, we have the distance from B to C.

Therefore, the distance from B to C is 5 cm.

5 cm