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November 28, 2014

November 28, 2014

Posted by **Annabella Richards** on Monday, June 20, 2011 at 2:06am.

- Maths -
**Dr Russ**, Monday, June 20, 2011 at 10:10amStart with a number AB which is 10A+B

and the reverse is 10B+A

using the information in the question

3(10A+B)-4(10B+A)=8

26A-37B=8

Now neither A or B can be zero (0A or 0B is not a valid number)

also we can say that if B>=A then the result is negative.

We can from the equation infer that A is only slightly larger than B

So I tred

A=5 B=3

A=6 B=4

A=7 B=5

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