Posted by **Joshua** on Monday, June 20, 2011 at 1:12am.

A horizontal massless beam of length 1 m is supported at two points. One fulcrum is at one end of the beam, point "O", and the other at the 0.60m point "P". Two equal weights are placed on the beam, one at O and one at point Q at distance x from O. Find the value of x that will result in the support force at P being twice the magnitude as the support force at O.

## Answer This Question

## Related Questions

- Physics - A beam that weighs 10.0 N/m is 2.5m long. It is supported at point a ...
- Physics - A uniform steel beam of length 5.50 m has a weight of 4.50 103 N. One ...
- Physics - A uniform steel beam of length 5.50 m has a weight of 4.50 103 N. One ...
- physics - A 30.0-kg child sits on one end of a long uniform beam having a mass ...
- physics - a uniform beam 6.0 metre long and weighing 4kg rests on support at p ...
- physics - A uniform, horizontal beam is 5.00m long and has a weight of 200N. The...
- Physics - A 1230 N beam is attached to a vertical wall at one end and is ...
- Physics - A beam of mass mb = 10.0 kg, is suspended from the ceiling by a ...
- Physics! plese help - A 1320-N uniform beam is attached to a vertical wall at ...
- Physics - A uniform beam weighing Wa=1200 N is 3.50 m long and is suspended ...

More Related Questions