Posted by **Yetty** on Sunday, June 19, 2011 at 6:16pm.

find equation of a tangent line to y=x^3-5x+6 at the point where x=2

- calculus -
**Damon**, Sunday, June 19, 2011 at 7:02pm
Now this is the last one. These are basis and you should try them.

dy/dx = slope = m = 3x^2 -5

at x = 2, m = 12-5 = 7

so line is of form

y = 7x+b

at x = 2, y = 8-10+6 = 4

so tangent at point (2,4)

4 = 14+b

so

b = -10

so

y = 7 x -10

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