if a rocket is launched upward at 80fett per second. what will its height be at (t) seconds later s= 80t-14t^2
You have the right formula. Given a time t, you can calculate altitude s
To find the height of the rocket at a given time, we can use the given equation:
s = 80t - 14t^2
Here's how to solve it:
1. Substitute the value of "t" into the equation. Let's say we want to find the height at time "t" seconds:
s = 80(t) - 14(t)^2
2. Simplify the equation:
s = 80t - 14t^2
3. Calculate the height by plugging in the value for "t":
For example, if we want to find the height at t = 5 seconds, we plug in 5 for "t" in the equation:
s = 80(5) - 14(5^2)
s = 400 - 14(25)
s = 400 - 350
s = 50
Therefore, the height of the rocket at 5 seconds would be 50 feet.