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March 3, 2015

March 3, 2015

Posted by **Elisa** on Sunday, June 19, 2011 at 11:11am.

- intermidiate Algebra -
**MathMate**, Sunday, June 19, 2011 at 3:23pm16y^7+32y^5+80y^3

=16y³(y^4+2y²+5)

One possible set of dimensions is

16y³ m. x (y^4+2y³+5) m.

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