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Posted by **kavita** on Sunday, June 19, 2011 at 4:05am.

(i) the horizontal distance between the pole and the tower

(ii) the height of the pole

- math -
**Reiny**, Sunday, June 19, 2011 at 9:03amTough to figure out from the "non-given" diagram.

let DB, the horizontal distance be x.

angle ADB = 48 degrees, 30 minutes (not inches!)

= 48.5°

so tan 48.5 = 40/x

x = 40/tan48.5 = 35.39 m

from C, draw a horizontal to meet AB at E

tan 24.5 = AE/x

AE = xtan24.5 = 16.13 m

so height of pole = BE = 40-16.128 = 23.87 m

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