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March 5, 2015

March 5, 2015

Posted by **lucky** on Sunday, June 19, 2011 at 3:59am.

- math -
**Reiny**, Sunday, June 19, 2011 at 8:52amlet the ladder reach h m high on the wall, let the base angle be Ų

sinŲ = h/5

h = 5sinŲ

dh/dt = 5cosŲ dŲ/dt

given: dh/dt = -10m/sec

when base = 2m, cosŲ = 2/5

-10 = 5(2/5) dŲ/dt

dŲ/dt = -5 radians/sec

the angle is decreasing at a rate of 5 radians / sec

(by using the word "decreasing" I do not include the negative sign)

- math -
**JANARDHAN**, Monday, March 3, 2014 at 10:05amChange first 5m to 500cm and 2m to 200cm and then solve using above procedure of reiny answer is 1/20 radians/sec

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