Algebra
posted by Jack on .
4x+2y3z=7 2x+4y+z=35 6x+2y2z=20 solve the system

#1 + 3(#2) > 10x + 14y = 112 or 5x + 7y = 56 (#4)
#3 + 2(#2) > 10x + 10y = 90 or 5x + 5y = 45 (#5)
#4  #5 > 2y = 11
y = 5.5
in #5 > x + 5.5 = 9
x = 3.5
in #2
2(3.5) + 4(5.5) + z = 35
z = 6
I will leave it up to you to check those answers.