a balloon can hold 800ml of air before breaking. A balloon at 4 deg C contain 750ml of air is brought into a house at 25 deg C. Assuming a constant pressure inside and outside the ballon, will the balloon break?
V2/750= (273+25)/(273+4)
solve for V2
To determine if the balloon will break when brought into a house at a higher temperature, we need to compare the initial volume of air inside the balloon at 4°C to its final volume at 25°C.
We can use Charles's Law to find the final volume of air inside the balloon. Charles's Law states that at constant pressure, the volume of a gas is directly proportional to its temperature. The formula for Charles's Law is:
V1 / T1 = V2 / T2
Where V1 and T1 represent the initial volume and temperature, respectively, and V2 and T2 represent the final volume and temperature, respectively.
Let's plug in the values we have:
V1 = 750 ml (initial volume)
T1 = 4°C = 277K (initial temperature)
T2 = 25°C = 298K (final temperature)
Plugging the values into the formula, we get:
750 ml / 277K = V2 / 298K
Next, we can solve for V2 (final volume):
V2 = (750 ml / 277K) * 298K
V2 ≈ 807 ml
The final volume of the air inside the balloon at 25°C is approximately 807 ml.
Since the balloon can hold a maximum of 800 ml of air, and the final volume is slightly larger than this, it is likely that the balloon will break when brought into the house at 25°C. However, it's important to note that other factors, such as the elasticity of the balloon, could also influence whether it breaks or not.