a balloon can hold 800ml of air before breaking. A balloon at 4 deg C contain 750ml of air is brought into a house at 25 deg C. Assuming a constant pressure inside and outside the ballon, will the balloon break?
What formula would be used here?
see other post.
To determine whether the balloon will break, we need to apply Charles's Law. Charles's Law states that at constant pressure, the volume of a gas is directly proportional to its temperature in Kelvin.
The formula for Charles's Law is:
V1/T1 = V2/T2
Where:
V1 is the initial volume of the gas
T1 is the initial temperature of the gas in Kelvin
V2 is the final volume of the gas
T2 is the final temperature of the gas in Kelvin
In this case, we can use the formula to compare the initial and final volumes of the air inside the balloon.
Given:
V1 = 750 ml (convert to liters by dividing by 1000: 750 ml / 1000 = 0.75 L)
T1 = 4°C + 273.15 (convert to Kelvin) = 277.15 K
V2 = ? (unknown)
T2 = 25°C + 273.15 (convert to Kelvin) = 298.15 K
Using the formula for Charles's Law, we can rearrange it to solve for V2:
V2 = (V1 x T2) / T1
Substituting the values:
V2 = (0.75 L x 298.15 K) / 277.15 K
Now, we can calculate the value of V2:
V2 ≈ 0.806 L
The final volume, V2, is approximately 0.806 liters.
Since the final volume of the air inside the balloon at 25°C (0.806 L) is less than the maximum capacity of the balloon (0.8 L), the balloon will not break.