Posted by Smartypants on Saturday, June 18, 2011 at 12:51am.
1. Cost = $30/X per orange.
2. Selling Price = (30/X+0.05)per orange.
3. (30/X + 0.05)(X - 20) = 28,
Multiply the 2 binomials and get:
30 - 600/X + 0.05X - 1 = 28,
Multiply both sides by X:
30X - 600 + 0.05X^2 - X = 28X,
0.05X^2 + 29X - 600 = 28X,
0.05X^2 + 29X - 28X - 600 = 0,
0.05X^2 + X - 600 = 0,
Multiply both sides by 20:
X^2 + 20X - 12000 = 0.
But your solution of this problem doesn't show the stuff that any real businessman would want to know. How many oranges? What is my unit cost in actual cents not formula? When will I be in profit? etc
Thanks a lot Henry! Your working is right!
Btw, thank too Raymond for helping me out, I appreciate it a lot (:
Appreciate both of you who help me! Thanks!!!!!
Btw Henry, why multiply by 20 in the end? Is it because he had sold all except 20 of the oranges?
Related Questions
Math algebra (urgent!) help me! Thanks a lot!! (; - Mr lol bought x oranges for...
Math - Mr.Santiago brought 10 crates of oranges. There were 50 oranges in each ...
Math - The question is: A Woman is selling an (X) amount of Oranges The first ...
math - jasmine bought 26 pieces of fruit.she bought 6 oranges.she bought twice ...
Math - Oranges are on sale at $0.99 per pound. Either bought 3.25 pounds of ...
math - Mr. Havel bought a car for $2400 and sold it for $2700. what was the ...
9th grade - Celia bought 12 apples, ate two of them, and sold the rest at 20 ...
maths - Jill bought 10 manoges and 5 oranges. Chris bought 5 mangoes and 10 ...
algebra 2 - a grocer sold a total of 126 apples, oranges, and melons one day. ...
math investments - I am unsure how to figure out this question please explian Mr...
For Further Reading