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April 25, 2014

Posted by **Smartypants** on Saturday, June 18, 2011 at 12:51am.

(ii)the selling price of an orange

When he had sold all except 20 of the oranges, he found he had received $28.

(iii) form an equation in x and show that it simplifies to xsquare + 20x -12000= 0

- Math -
**Henry**, Saturday, June 18, 2011 at 3:29pm1. Cost = $30/X per orange.

2. Selling Price = (30/X+0.05)per orange.

3. (30/X + 0.05)(X - 20) = 28,

Multiply the 2 binomials and get:

30 - 600/X + 0.05X - 1 = 28,

Multiply both sides by X:

30X - 600 + 0.05X^2 - X = 28X,

0.05X^2 + 29X - 600 = 28X,

0.05X^2 + 29X - 28X - 600 = 0,

0.05X^2 + X - 600 = 0,

Multiply both sides by 20:

X^2 + 20X - 12000 = 0.

- Math -
**Raymond**, Saturday, June 18, 2011 at 5:15pmBut your solution of this problem doesn't show the stuff that any real businessman would want to know. How many oranges? What is my unit cost in actual cents not formula? When will I be in profit? etc

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**Click6**, Saturday, June 18, 2011 at 11:00pmThanks a lot Henry! Your working is right!

Btw, thank too Raymond for helping me out, I appreciate it a lot (:

- Math -
**Click6**, Saturday, June 18, 2011 at 11:02pmAppreciate both of you who help me! Thanks!!!!!

- Math -
**Click6**, Saturday, June 18, 2011 at 11:56pmBtw Henry, why multiply by 20 in the end? Is it because he had sold all except 20 of the oranges?

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