Posted by Kelley on Friday, June 17, 2011 at 10:10pm.
f(t)=6/t
t1=a, t2=a+h
average rate of change
= Δf(t)/Δt
=(f(a+h)-f(a))/(a+h-a)
=(6/(a+h)-6/a))/(h)
=(6/h)(1/(a+h)-1/a)
...
simplify to get final answer.
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