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March 5, 2015

March 5, 2015

Posted by **Kelley** on Friday, June 17, 2011 at 10:10pm.

f(t) =

6/t

; t = a, t = a + h

- college algebra -
**MathMate**, Saturday, June 18, 2011 at 7:18amf(t)=6/t

t1=a, t2=a+h

average rate of change

= Δf(t)/Δt

=(f(a+h)-f(a))/(a+h-a)

=(6/(a+h)-6/a))/(h)

=(6/h)(1/(a+h)-1/a)

...

simplify to get final answer.

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