Chemistry
posted by Amanda on .
Please help me with the following question:
Consider the following ion; XF22
What is the oxidation number assigned to element “X”? Show your work
I'm having trouble writing the steps.

Just follow the rules.
F is 1; there are two of them to make 2. The XF2^2 ion must be left with a charge of 2.
X + 2F = 2
X + 2(1) = 2
X 2 = 2
X = 2+2 = 0
X must have an oxidation state of zero.