A CAR HAS A MASS OF 1200KG TRAVELLING ON A LEVEL ROAD. THE CAR DECELERATED AT A RATE OF 10M/S^2 TILL THE CAR STOPPED. iT HAS TO OVERCOME A TOTAL RESISTANCE OF 400N WHILE BRAKING.

(I) CALCULATE THE BRAKING FORCE OF THE CAR
(II) WHAT WAS THE DRIVING OF CAR OF THE CAR?

The total force decelerating the car was

F = M a = 120,000 N

The numbers you have presented don't make sense.

Neither does Part II of your question

To calculate the braking force of the car, you can use Newton's second law of motion which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.

Given:
Mass of the car (m) = 1200 kg
Deceleration (a) = -10 m/s^2 (negative sign indicates deceleration)

(I) Calculation of the braking force:
Using Newton's second law formula:
Force (F) = mass (m) * acceleration (a)

Substituting the given values:
F = 1200 kg * (-10 m/s^2)
F = -12,000 N

Therefore, the braking force of the car is -12,000 N. The negative sign indicates that it acts in the opposite direction to the motion of the car.

(II) Calculation of the driving force of the car:
The driving force acts in the direction of the car's motion and is equal in magnitude but opposite in direction to the resistance force the car needs to overcome while braking. So, we can use the same value, but with the opposite sign.

Driving force = Resistance force = -400 N

Therefore, the driving force of the car is -400 N.