March 29, 2017

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please verify my answer:

Consider the following REDOX reaction:
Zn(s) + Pb+2(aq) �� Zn+2(aq) + Pb(s)

a. Write the oxidation and reduction half-cell reactions.

Zn(s) + Pb+2(aq) �� Zn+2(aq) + Pb(s)
+2 +4 +2 +4

Zn(s)->Zn2+(aq)+2e- (zinc is oxidized)
Pb2+(aq)+2e- ->Pb(s)(lead is reduced)

b. Show this reaction in shorthand notation. (2 marks)

Zn(s)| Zn2+(aq) || Pb2+(aq) | Pb(s)

If it's wrong please tell me how. Thank you for your help :)

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