Mat 116 Algebra 1A
posted by Martin on .
7[3m(m+2)]>6(m+3)
Use setbuilder notation to describe the complete solution
{mm > ? }
(type an equality symbol; then type an integer or a simplified fraction.)

7[3m(m+2)] > 6(m+3).
Since the absolute value of a positive
number is = the absolute value of a negative number of the same magnitude,
we have 2 solutions.
+7(3m(m+2)) > 6(m+3),
+7(3mm2) > 6m18,
7(2m2) > 6m18,
14m14 > 6m18,
14m + 6m > 18 + 14,
20m > 4,
m > 1/5.
7(3m(m+2)) > 6(m+3),
7(3mm2) > 6m18,
7(2m2) > 6m18,
14m + 14 > 6m18,
14m + 6m > 1814,
8m > 32,
m < 4.
Solution set: m > 1/5, and m < 4.
OR
1/5 < m < 4.