Posted by Ben on .
Find the derivative.
11) f(t)=(1)/(sqrt(8t3))
12) g(t)= ((4t3)^2)/ ((5t+1)^4)
Thanks.

derivative 
bobpursley,
These are standard formulas...
f()= 1/u
f'=u'/u^2 where u is sqrt(8t3), u'=4/sqrt( )
g= u/v
g'=uv'/v^2 + u'/v where u=(4t3)^2 v=(5t+1)^4
I assume you can do it from here.