Posted by Kelly on Wednesday, June 15, 2011 at 3:25pm.
You want Z scores that cut off .15 (15%) of the students either direction from the mean.
Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion and put its Z score with the other values in the above equation. Solve for the score (both ±).
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