Posted by **mukesh** on Wednesday, June 15, 2011 at 10:53am.

in a class 1/3 of students play cricket 1/8 play volleyball, 1/6 play tennis and the rest don't play any games. what fraction of the students doesn't play any games?

- maths -
**Jai**, Wednesday, June 15, 2011 at 11:11am
first we add all the fractions:

1/3 + 1/8 + 1/6

to add them, we need the 'least common denominator' (LCD) of the three fractions. LCD is the smallest number that is divisible by 3, 8 and 6.

the LCD of 3, 8 and 6 is 24. then we change all the denominators by 24. to get the new numerator for each, we divide 24 by the original denominator then multiply by original numerator.

for example, 1/3. we divide 24 by 3 and we get 8, then multiply by original numerator (which is 1) and thus the new numerator is 8. and we can say that 1/3 is equivalent to 8/24. applying this to the other two fractions,

8/24 + 3/24 + 4/24

to add fractions, just copy the denominator and add the numerators:

15/24

finally, we are asked of the fraction that does NOT play games. therefore, we subtract this from 1 (because 1 or one whole represent the whole class). therefore,

1 - 15/24 = 9/24 or 3/8

hope this helps~ :)

- maths -
**fdhythu**, Monday, December 14, 2015 at 4:00am
vollyball

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