Posted by **ameer** on Wednesday, June 15, 2011 at 8:15am.

3. At t = 0 , a particle leaves the origin with a velocity of 9.0 m/s in the positive y direction and moves in the xy plane with constant accelaration of ( 2.0i - 4.0j ) m/s2 . At the instant the x coordinate of the particle is 15 m , what is the speed of the particle ?

- uniten -
**bobpursley**, Wednesday, June 15, 2011 at 9:17am
Vf=Vi+at

Vf=9j+(2i-4j)t

displacement= origposition+at

now, in the i direction

15=O+2t or t=7.5 when x position is 15

put that into the first equation, solve for Vf.

speed= sqrt (xcomponent^2+ycomponent^2)

you get the x component, y component in the Vf equation

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