Chemistry
posted by Dexter on .
Please help me verify the following question:
Consider the following ion; XF22
What is the oxidation number assigned to element “X”? Show your work
My answer:
X F22
X 1(1)
X 3=0
X = +3
Please let me know if right. Many thanks!

Nope. If X = 3, then XF2^2 would be +3 for X, 2 for two F, so the charge would be +1. Try X = 0. Each F is 1 for a total F of 2. Then 0 for X + (2) for F leaves a charge of 2 on the ion which it has.

Having it explained that way makes it easier to understand and helps to verify answer in the end which my course didn't explain. Thank you.