a 250.0 mL of solution contains 50.0 mL acetone and 45.0 mL ethyl alcohol and the remainder water. Calculate the % acetone,

% ethyl alcohol, and water in the solution. Show calculations.

20.0% acetone

18.0% Ethyl Alcohol
62.0% water

You take the mL you're trying to find divided by the whole solution, then multiply by 100.

For example, you have 50.0mL/250.0mL = 0.20
Take 0.20 x 100 and it will give you the percent.

To calculate the percentage of each component in the solution, we need to convert the volumes into percentages.

First, let's calculate the volume of water in the solution:
Volume of water = Total volume of solution - Volume of acetone - Volume of ethyl alcohol
= 250.0 mL - 50.0 mL - 45.0 mL
= 155.0 mL

Now, let's calculate the percentage of each component:
% acetone = (Volume of acetone / Total volume of solution) * 100
= (50.0 mL / 250.0 mL) * 100
= 20.0%

% ethyl alcohol = (Volume of ethyl alcohol / Total volume of solution) * 100
= (45.0 mL / 250.0 mL) * 100
= 18.0%

% water = (Volume of water / Total volume of solution) * 100
= (155.0 mL / 250.0 mL) * 100
= 62.0%

Therefore, the solution contains 20.0% acetone, 18.0% ethyl alcohol, and 62.0% water.