2) Find the minimum sample size that should be chosen to assure that the proportion estimate p will be within the required margin of error, .06. Use a 95% confidence interval and a population proportion of .7. The critical value for a 95% confidence level is 1.96

To find the minimum sample size needed to assure that the proportion estimate p will be within the required margin of error, we can use the following formula:

n = (Z^2 * p * (1 - p)) / E^2

Where:
- n is the minimum sample size required
- Z is the critical value for the desired confidence level (1.96 for a 95% confidence level)
- p is the estimated population proportion
- E is the desired margin of error

Using the given values, we can substitute them into the formula:

n = (1.96^2 * 0.7 * (1 - 0.7)) / 0.06^2

Simplifying the equation:

n = (3.8416 * 0.7 * 0.3) / 0.0036
= 1.0759 / 0.0036
≈ 298.86

Therefore, the minimum sample size that should be chosen to assure that the proportion estimate p will be within a margin of error of 0.06, with a 95% confidence level and a population proportion of 0.7, is approximately 299 samples.