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December 17, 2014

December 17, 2014

Posted by **Mctagger** on Tuesday, June 14, 2011 at 11:53am.

A) 3+7 10 mod 15

17 + 9 4 mod 21

12 + 14 0 mod 26

B) 4+11 2 mod 13

9+7 4 mod 12

13 + 13 1 mod 25

C) 5+9 4 mod 10

16 + 13 3 mod 26

12 + 7 6 mod 14

d)2+7 9 mod 15

15 + 15 6 mod 22

8+5 2 mod 10

e)7+11 1 mod 18

6+13 9 mod 26

4+20 2 mod 22

F )13 + 19 6 mod 26

6+12 4 mod 14

17+ 10 9 mod 18

- math -
**MathMate**, Tuesday, June 14, 2011 at 1:27pmA)

3+7 ≡ 10 mod 15

3+7=10, 10÷15=0 remainder 10:TRUE.

17 + 9 ≡ 4 mod 21

17+9=26; 26÷21 Remainder=5: FALSE

12 + 14 ≡ 0 mod 26

12+14=26; 26÷26=1 remainder 0:TRUE

You can attempt the rest, and post your answers for checking if you wish.

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