Posted by Susie on Tuesday, June 14, 2011 at 10:07am.
Perform the indicated operations and simplify.
y4/y9  y+1/y+9 + y99/y^281

algebra  bobpursley, Tuesday, June 14, 2011 at 10:43am
common denominator: (y+9)*(y9)
I think this is what you meant.
(y4)(y+9) (y+1)(y9) (y9) all that over the denominator.
y^2+5y36 y^2+8y+9 y+9 over the denominator.
12y 27 over the denominator
3(4y9) over the denominator. 
algebra  MathMate, Tuesday, June 14, 2011 at 10:45am
I have made a guess and put on the minimum parentheses for the problem to make sense. Do not forget to enclose numerators and denominators with parentheses when transcribing expressions from a book or other sources.
(y4)/(y9)  (y+1)/(y+9) + (y99)/(y^281)
using (y9)(y+9)=y²81
=(y4)/(y9)  (y+1)/(y+9) + (y99)/((y+9)(y9))
=((y4)(y+9)(y+1)(y9)+(y99))/((y+9)(y9))
=(y²+5y36  (y²8y9) + (y99))/((y+9)(y9))
=(14y126)/((y+9)(y9))
=14(y9)/((y+9)(y9))
=14/(y+9)