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Posted by **Susie** on Tuesday, June 14, 2011 at 10:07am.

y-4/y-9 - y+1/y+9 + y-99/y^2-81

- algebra -
**bobpursley**, Tuesday, June 14, 2011 at 10:43amcommon denominator: (y+9)*(y-9)

I think this is what you meant.

(y-4)(y+9) -(y+1)(y-9) -(y-9) all that over the denominator.

y^2+5y-36 -y^2+8y+9 -y+9 over the denominator.

12y -27 over the denominator

3(4y-9) over the denominator.

- algebra -
**MathMate**, Tuesday, June 14, 2011 at 10:45amI have made a guess and put on the minimum parentheses for the problem to make sense. Do not forget to enclose numerators and denominators with parentheses when transcribing expressions from a book or other sources.

(y-4)/(y-9) - (y+1)/(y+9) + (y-99)/(y^2-81)

using (y-9)(y+9)=y²-81

=(y-4)/(y-9) - (y+1)/(y+9) + (y-99)/((y+9)(y-9))

=((y-4)(y+9)-(y+1)(y-9)+(y-99))/((y+9)(y-9))

=(y²+5y-36 - (y²-8y-9) + (y-99))/((y+9)(y-9))

=(14y-126)/((y+9)(y-9))

=14(y-9)/((y+9)(y-9))

=14/(y+9)

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