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December 18, 2014

December 18, 2014

Posted by **Chelsie** on Monday, June 13, 2011 at 9:29pm.

- Math -
**Reiny**, Monday, June 13, 2011 at 9:52pmI will use a for alpha and b for beta

sin a = 4/√65 , then cos a = -7/√65 in II

tana = sina/cosa = -4/7

cosb = -3/√13 , then sin b = -2/√13 in III

tanb = 2/3

tan(a+b) = (tana + tanb)/(1 - tanatanb)

= (-4/7 + 2/3)/(1 - (-4/7)(2/3))

= 2/29

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