a stone falls from a cliff and travels 34.3 in the last second before it reaches the ground. calculate the height of the cliff?

Why are you posting this again? I answered it yesterday.

http://www.jiskha.com/display.cgi?id=1307893011

To calculate the height of the cliff, we can use the kinematic equation for vertical motion:

S = ut + (1/2)at^2

Where:
S = Distance or height (unknown in this case)
u = Initial velocity (zero in this case since the stone starts at rest)
t = Time taken (1 second in this case)
a = Acceleration due to gravity (-9.8 m/s^2)

Since the stone falls downward, we take acceleration due to gravity as negative (-9.8 m/s^2).

Substituting the given values into the equation:

34.3 = (0) * 1 + (1/2) * (-9.8) * 1^2

Simplifying the equation:

34.3 = -4.9

This equation appears to be incorrect since the left-hand side is positive, but the right-hand side is negative. So, there seems to be some error in the given information or the calculation.

Please double-check the values provided and ensure that all the necessary information is available (such as the initial velocity or time taken).